Catenary
Explore the symmetric catenary curve supported at its ends and compare its shape to a parabola.
Free theory articleExplore the symmetric catenary curve supported at its ends and compare its shape to a parabola.
Concept & interpretation
The catenary is the shape assumed by a hanging flexible inextensible chain or cable supported at its ends and subjected only to a uniform gravitational force. The name derives from the Latin word "catena," meaning chain. Its symmetric equation is given by the hyperbolic cosine function: y = a * (cosh(x / a) - 1)
Interactive Experiment
Use the Catenary interactive module to explore how changes in tension, weight, and span affect the shape and length of the hanging chain.
- Set Catenary scale a to 1, Half-span L to 1, and Probe fraction u to 0. Observe the selected point at the lowest point (0,0). The support sag is
cosh(1) - 1 ≈ 0.543081and the total length is2 * sinh(1) ≈ 2.350402. - Change the Probe fraction u to -1. The selected point height now equals the right support sag, and the slope is
-sinh(1), showing the reflection symmetry of the curve. - Set Catenary scale a to 0. The module rejects the nonpositive scale, demonstrating that tension must be strictly positive to maintain the shape; division by zero is avoided.
- Restore Catenary scale a to 1, then set Half-span L to 0 with Probe fraction u at 1. The supports coincide at (0,0), and the span, sag, length, and slope all become 0. This is labeled the collapsed-span limit.
- Set Catenary scale a to 0.5, Half-span L to 3 and Probe fraction u to 1. Read finite sag approximately 100.357818061 m and length 201.713157370 m; both supports and the low point fit the independent labelled axes.
- Set Catenary scale a to 3, Half-span L to 0.00000001 and Probe fraction u to 1. The small positive sag is about 1.66666666667e-17 m, displayed in scientific notation rather than replaced with zero.
- Compare the solid cyan catenary with the dashed parabola. While they look similar near the origin, they diverge significantly further out.